dhtmlxgrid_form - Index and Row ID question

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#1

I am using the dhtmlxgrid_form.js to send a grid to PHP using the $_POST variables and I have encountered a problem.



I have a grid with three lines. I move the third line up to the the top of the grid. Now the index of the third line is 0. When I click on submit and recover the $_POST variables, the third line which has an index of 0 still shows up as the third line in the $_POST.



So imagine I have a table with 3 rows

Row 1 Test 1

Row 2 Test 2

Row 3 Test 3



I move the third row up to the top. Now I have

Row 3 Test 3

Row 1 Test 1

Row 2 Test 2



When the data is sent to PHP, I get the data back the order in which it was originally created.

Row 1 Test 1

Row 2 Test 2

Row 3 Test 3



Is there way to send the data to PHP based on each row’s index and not its ID? Or is there a way to change the ID of the row to match the index every time it is moved

#2

Actually there was not any special meaning in order of data inside POST sending, it just a not-expected side effect that data sent in same order as rows loaded in grid.


dhtmlxgrid_form.js , line 156



this.forEachRow(function(id){
this._createInputRow(this.rowsAr[id]);
})
can be replaced with
for (var i=0; i<this.rowsBuffer.length; i++)
this._createInputRow(this.rowsBuffer[i]);

It will change behavior of “send all” mode, so order of parameters will be equal to order of rows in grid.




#3

  this.forEachRow(function(id){
              this._createInputRow(this.rowsAr[id]);
            })

was actually in the dhtmlxgrid_form.js and not in the dhtmlxgrid.js.    Your solution did work however

Craig