get complex header label after split

Suite and Optimus Suite 5
#1

Hi,

I have a grid with a header containing columnheaders with html.
I need to get the html inside some of these columns. I found the method mygrid.hdr.rows[row_index].cells[cellindex] to get the td so you can read the td content.

The problem is that the grid is split and I need to get to the columns to the right of the split. mygrid.hdr.rows[row_index] only returns the columns to the left of the split.

Is there a way to access the columnheaders on the right of the split so I can get to the innerHTML of those columnheaders?

thanks and kind regards,
Arno.

#2

In the same way I need to be able to set complex content in the header after the split.
In fact there’s an image with a link, next to some text in that columnheader and I need to change the image of that link. So it’s getting complex content from the header after split, changing it and setting it back after the split.

kind regards,
Arno.

#3

To get content of header cell in left part of the grid you may use following code:

mygrid._fake.hdr.rows[row_index].cells[cellindex]

#4

The left side isn’t the problem, I figured that out myself, but it’s the right side that I can’t get to.

If I use grid._fake.hdr it only contains the columns of the left side, not the right side.

kind regards,
Arno.

#5

You should use different objects for left and right parts.
grid._fake.hdr for left part
grid.hdr for right part

#6

Thank you very much!

I was a bit confused because grid.hdr also gave me the left part, but in fact it gives the whole header ignoring the split and counting spanned columns as 1 column.

Thank you!

Kind regards,
Arno.