hello,
The DataProcessor was must to be init(same Object for dhtmlx)?
I want to only used DataProcessor to send same data,how to do?
var dp = new dataProcessor(“php/update.php”);?
what is senddata dataformat or parameter?
hello,
The DataProcessor was must to be init(same Object for dhtmlx)?
I want to only used DataProcessor to send same data,how to do?
var dp = new dataProcessor(“php/update.php”);?
what is senddata dataformat or parameter?
If you want to make an arbitrary ajax call, it will be better to use dhx4.ajax methods instead.
docs.dhtmlx.com/api__dhtmlxajax_post.html
If you need to send some data along with normal dataprocessor packages, you can embed the data directly in the URL
var dp = new dataProcessor("php/update.php?data=abc&other=123");