tree.serializeTree() takes no parameters therefore indicating that the whole tree is serialized. Is it possible (or planned feature) to create a serialised tree (branch) starting at and nominated node?
This approach is not documented:
tree._serializeItem(tree._idpull["mystery"])Thanks for the response. Based on the shortness thereof it would appear that such feature is to remain undocumented 
Without experimentation I’m guessing that _idpull retrieves all the nodes from and including the node which is labelled “mystery”. What if there are two unique (id) nodes that share the same label?
Sorry, that misled you. This method is private - therefore it is not documented. We can’t guarantee 100 % its work in all cases.
Apropos “mistery” is in my example - it is the id of an item “Mystery”.
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