update event programmatically and send changes to the server

[MisterRG]

Hi !

I have a scheduler with dataprocessor enabled like this :

scheduler.setLoadMode("day"); scheduler.load("/ajax/ajax_get_rdvs.php","json"); var dp = new dataProcessor("/ajax/ajax_get_rdvs.php"); dp.init(scheduler);

I have a contextMenu wich from the user can change the end date of an event. When I change the event property end_date I’m doing :

var s_date_e = new Date(the_date.getFullYear(),the_date.getMonth(),the_date.getDate(),hame.hours,hame.minutes,0,0); var e_date_s = new Date(the_date.getFullYear(),the_date.getMonth(),the_date.getDate(),hpms.hours,hpms.minutes,0,0); ev.start_date = s_date; ev.end_date = s_date_e; ev.missed_hours_reason= missed_hour_reason; scheduler.updateEvent(ev.id);
And, from the documentation :

Updating data

If you have dataProcessor initialized, any change made by the user or programmatically will be automatically saved in the data source.

Generally, to update a specific event programmatically, use the updateEvent method

The event is correctly rendered in the scheduler, but the dataprocessor does not update the event on the server side.

Any clue on this issue ?

Thanks in advance

[SergeM]

Hi,
the “scheduler.updateEvent()” only renders the event in the scheduler, so makes the changes visible. It doesn’t send any data to the server-side. To do this you can call “onEventChanged” event:

scheduler.updateEvent(ev.id); scheduler.callEvent("onEventChanged", [ev.id, ev]);
docs.dhtmlx.com/scheduler/api__s … event.html
And the dataProcessor will catch it and will update the data on the server.

[MisterRG]

It works perfectly, thanks a lot !

[hifzur08cs]

Excellent!!
I was also having same kind of problem, this worked perfectly for me also

Thanks